4(n^2-3x-9)=-8n-36

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Solution for 4(n^2-3x-9)=-8n-36 equation:


Simplifying
4(n2 + -3x + -9) = -8n + -36

Reorder the terms:
4(-9 + n2 + -3x) = -8n + -36
(-9 * 4 + n2 * 4 + -3x * 4) = -8n + -36
(-36 + 4n2 + -12x) = -8n + -36

Reorder the terms:
-36 + 4n2 + -12x = -36 + -8n

Add '36' to each side of the equation.
-36 + 4n2 + 36 + -12x = -36 + 36 + -8n

Reorder the terms:
-36 + 36 + 4n2 + -12x = -36 + 36 + -8n

Combine like terms: -36 + 36 = 0
0 + 4n2 + -12x = -36 + 36 + -8n
4n2 + -12x = -36 + 36 + -8n

Combine like terms: -36 + 36 = 0
4n2 + -12x = 0 + -8n
4n2 + -12x = -8n

Solving
4n2 + -12x = -8n

Solving for variable 'n'.

Reorder the terms:
8n + 4n2 + -12x = -8n + 8n

Combine like terms: -8n + 8n = 0
8n + 4n2 + -12x = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(2n + n2 + -3x) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(2n + n2 + -3x)' equal to zero and attempt to solve: Simplifying 2n + n2 + -3x = 0 Solving 2n + n2 + -3x = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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